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x^2-11x-32=-x
We move all terms to the left:
x^2-11x-32-(-x)=0
We add all the numbers together, and all the variables
x^2-11x-(-1x)-32=0
We get rid of parentheses
x^2-11x+1x-32=0
We add all the numbers together, and all the variables
x^2-10x-32=0
a = 1; b = -10; c = -32;
Δ = b2-4ac
Δ = -102-4·1·(-32)
Δ = 228
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{228}=\sqrt{4*57}=\sqrt{4}*\sqrt{57}=2\sqrt{57}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{57}}{2*1}=\frac{10-2\sqrt{57}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{57}}{2*1}=\frac{10+2\sqrt{57}}{2} $
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